Advertisements
Advertisements
Question
Differentiate the following with respect to x.
`sqrtx + 1/root(3)(x) + e^x`
Solution
Let y = `sqrtx + 1/root(3)(x) + e^x`
y = `x^(1/2) + x^(1/3) + e^x`
`[because 1/root(3)(x) = 1/(x^(1/3)) = x^(1/3)]`
`"dy"/"dx" = "d"/"dx" (x^(1/2)) + "d"/"dx" (x^(-1/3)) + "d"/"dx" (e^x)`
`= 1/2 x^(1/2 - 1) + ((- 1)/3) x^((-1)/3 - 1) + e^x`
`= 1/2 x^((-1)/2) - 1/3 1/(x^(4/3)) + e^x`
`= 1/2 1/(x^(1/2)) - 1/3 1/(x^(4/3)) + e^x`
`= 1/(2sqrtx) - 1/(3 root(3)(x^4)) + e^x`
APPEARS IN
RELATED QUESTIONS
Differentiate the following with respect to x.
`(3 + 2x - x^2)/x`
Differentiate the following with respect to x.
x3 ex
Differentiate the following with respect to x.
`e^x/(1 + e^x)`
Differentiate the following with respect to x.
cos3 x
Differentiate the following with respect to x.
`sqrt(1 + x^2)`
Differentiate the following with respect to x.
`1/sqrt(1 + x^2)`
If `xsqrt(1 + y) + ysqrt(1 + x)` = 0 and x ≠ y, then prove that `"dy"/"dx" = - 1/(x + 1)^2`
Differentiate the following with respect to x.
(sin x)tan x
If xy2 = 1, then prove that `2 "dy"/"dx" + y^3`= 0
If y = tan x, then prove that y2 - 2yy1 = 0.