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Karnataka Board PUCPUC Science Class 11

Dihydrogen Gas is Obtained from Natural Gas by Partial Oxidation with Steam as per Following Endothermic Reaction: How Will the Values of Kp and Composition of Equilibrium Mixture Be Affected by - Chemistry

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Question

Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction:

\[\ce{CH4 (g) + H2O (g) ⇌ CO (g) + 3H2 (g)}\]

How will the values of Kp and composition of equilibrium mixture be affected by

  1. increasing the pressure
  2. increasing the temperature
  3. using a catalyst?
Answer in Brief

Solution 1

(i) According to Le Chatelier’s principle, the equilibrium will shift in the backward direction.

(ii) According to Le Chatelier’s principle, as the reaction is endothermic, the equilibrium will shift in the forward direction.

(iii) The equilibrium of the reaction is not affected by the presence of a catalyst. A catalyst only increases the rate of a reaction. Thus, equilibrium will be attained quickly.

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Solution 2

  1. According to Le Chatelier’s principle, the equilibrium will shift in the backward direction.
  2. According to Le Chatelier’s principle, as the reaction is endothermic, the equilibrium will shift in the forward direction.
  3. The equilibrium of the reaction is not affected by the presence of a catalyst. A catalyst only increases the rate of a reaction. Thus, equilibrium will be attained quickly.
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Solution 3

(i) By increasing the pressure, the number of moles per unit volume will increase. In order to decrease the same, the equilibrium gets shifted to the left or in the backward direction. As a result, more of reactants will be formed and the value of Kp will decrease.

(ii) If the temperature is increased, according to Le Chatelier’s principle, the forward reaction will be favoured as it is endothermic. Therefore, the equilibrium gets shifted to the right and the value of Kp will increase.

(iii) The addition of catalyst will not change the equilibrium since it influences both the forward and the backward reactions to the same extent. But it will be attained more quickly.

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Solution 4

  1. By increasing the pressure, the number of moles per unit volume will increase. In order to decrease the same, the equilibrium gets shifted to the left or in the backward direction. As a result, more of reactants will be formed and the value of Kp will decrease.
  2. If the temperature is increased, according to Le Chatelier’s principle, the forward reaction will be favoured as it is endothermic. Therefore, the equilibrium gets shifted to the right and the value of Kp will increase.
  3. The addition of catalyst will not change the equilibrium since it influences both the forward and the backward reactions to the same extent. But it will be attained more quickly.
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Factors affecting equilibrium: Le Chatelier’s principle - Change of Temperature
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Chapter 7: Equilibrium - EXERCISES [Page 235]

APPEARS IN

NCERT Chemistry - Part 1 and 2 [English] Class 11
Chapter 7 Equilibrium
EXERCISES | Q 7.28 - (b) | Page 235

RELATED QUESTIONS

Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction:

\[\ce{CH4 (g) + H2O (g) ⇌ CO (g) + 3H2 (g)}\]

Write as the expression for Kp for the above reaction.


At 473 K, equilibrium constant Kc for decomposition of phosphorus pentachloride, PCl5is 8.3 ×10-3. If decomposition is depicted as,

\[\ce{PCl5 (g) ⇌ PCl3 (g) + Cl2 (g)}\]  ΔrH° = 124.0 kJmol–1

Write an expression for Kfor the reaction.


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\[\ce{PCl5 (g) ⇌ PCl3 (g) + Cl2 (g)}\]  ΔrH° = 124.0 kJmol–1

What is the value of Kc for the reverse reaction at the same temperature?


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\[\ce{PCl5 (g) ⇌ PCl3 (g) + Cl2 (g)}\]  ΔrH° = 124.0 kJmol–1

What would be the effect on Kc if

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