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Question
Divide:
Solution
\[\frac{\frac{1}{4} x^2 - \frac{1}{2}x - 12}{\frac{1}{2}x - 4}\]
\[ = \frac{\frac{1}{2}x(\frac{1}{2}x - 4) + 3(\frac{1}{2}x - 4)}{\frac{1}{2}x - 4}\]
\[ = \frac{(\frac{1}{2}x - 4)(\frac{1}{2}x + 3)}{(\frac{1}{2}x - 4)}\]
\[ = \frac{1}{2}x+3\]
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