Advertisements
Advertisements
Question
Divide:
(a2 + 2ab + b2) − (a2 + 2ac + c2) by 2a + b + c
Solution
\[\frac{( a^2 + 2ab + b^2 ) - ( a^2 + 2ac + c^2 )}{(2a + b + c)}\]
\[ = \frac{(a + b )^2 - (a + c )^2}{(2a + b + c)}\]
\[ = \frac{(a + b + a + c)(a + b - a - c)}{(2a + b + c)}\]
\[ = \frac{(2a + b + c)(b - c)}{(2a + b + c)}\]
\[ = b - c\]
APPEARS IN
RELATED QUESTIONS
Write the degree of each of the following polynomials.
Divide 72xyz2 by −9xz.
Divide 5x3 − 15x2 + 25x by 5x.
Divide 9x2y − 6xy + 12xy2 by −\[\frac{3}{2}\]
Divide 6x3 − x2 − 10x − 3 by 2x − 3 and find the quotient and remainder.
Divide 30x4 + 11x3 − 82x2 − 12x + 48 by 3x2 + 2x − 4 and find the quotient and remainder.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 14x2 + 13x − 15 | 7x − 4 |
Find whether the first polynomial is a factor of the second.
2a − 3, 10a2 − 9a − 5
Divide: 8x − 10y + 6c by 2
Divide 24(x2yz + xy2z + xyz2) by 8xyz using both the methods.
