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Divide 216 into three parts which are in A.P. and the product of two smaller parts is 5040. - Mathematics

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Question

Divide 216 into three parts which are in A.P. and the product of two smaller parts is 5040.

Sum

Solution

Let the three parts of 216 in A.P. be (a – d), a, (a + d).

`\implies` a – d + a + a + d = 216

`\implies` 3a = 216

`\implies` a = 72

Given that the product of two smaller parts is 5040.

`\implies` a(a – d) = 5040

`\implies` 72(72 – d) = 5040

`\implies` 72 – d = 70

`\implies` d = 2

∴ a – d = 72 – 2 = 70, a = 72 and a + d = 72 + 2 = 74

Therefore, the three parts of 216 are 70, 72 and 74.

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Simple Applications of Arithmetic Progression
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Chapter 10: Arithmetic Progression - Exercise 10 (F) [Page 148]

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Selina Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
Exercise 10 (F) | Q 21 | Page 148
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