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Maharashtra State BoardSSC (English Medium) 9th Standard

Divide first polynomial by second polynomial and write the answer in the form ‘Dividend = Divisor × Quotient + Remainder’. 5x5+4x4-3x3+2x2+2;x2-x - Algebra

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Question

Divide first polynomial by second polynomial and write the answer in the form ‘Dividend = Divisor × Quotient + Remainder’.

`5x^5 + 4x^4 - 3x^3 + 2x^2 +2;x^2-x`

Sum

Solution

              5x3 + 9x2 + 6x + 8
`x^2 - x)overline(5x^5 + 4x^4 - 3x^3 + 2x^2 + 2)`
               5x5 - 5x4
               -        +                            
                       9x4 - 3x3 + 2x2 + 2
                       9x4 - 9x3      
                       -        +                       
                                6x3 + 2x2 + 2
                                6x3 - 6x2
                              -        +                
                                         8x2 + 2
                                         8x2 - 8x
                                      -         +           
                                                 8x + 2

Dividend = Divisor ×​ Quotient + Remainder

`5x^5 + 4x^4 - 3x^3 + 2x^2 +2 = (x^2 - x) xx (5x^3 + 9x^2 + 6x + 8) + (8x + 2)`

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Operations on Polynomials
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Chapter 3: Polynomials - Practice Set 3.2 [Page 43]

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Balbharati Algebra (Mathematics 1) [English] 9 Standard Maharashtra State Board
Chapter 3 Polynomials
Practice Set 3.2 | Q (5) (ii) | Page 43
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