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Maharashtra State BoardSSC (English Medium) 8th Standard

Divide. Write the quotient and the remainder. (−48p4) ÷ (−9p2) - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Divide. Write the quotient and the remainder.

(−48p4) ÷ (−9p2)

Sum

Solution

 (−48p4) ÷ (−9p2)

= `(-48p^4)/(-9p_2)`

= `(-(16xx3xxp^2xxp^2))/(-(3xx3xxpxxp))`

= `(-48p^4)/(-9p_2)`

= `(16p^2)/3`

Division = opposite operation of multiplication.

         `(16/3)p^2`
`-9p^2")"overline(-48p^4) `
            - 48p
              +      
                 0

∴ quotient = `(16/3)p^2 ` & Remainder = 0

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Chapter 10: Division of Polynomials - Practice Set 10.1 [Page 64]

APPEARS IN

Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 10 Division of Polynomials
Practice Set 10.1 | Q 3 | Page 64
Balbharati Integrated 8 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.1 Division of Polynomials
Practice Set 10.1 | Q 1. (3) | Page 39
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