Advertisements
Advertisements
Question
Draw a ray diagram showing the image formation by a compound microscope. Hence obtained expression for total magnification when the image is formed at infinity.
Solution
A compound microscope consists of two convex lenses co-axially separated by some distance. The lens nearer to the object is called the objective. The lens through which the final image is viewed is called the eyepiece.
Magnifying power, when final image is at infinity:
The magnification produced by the compound microscope is the product of the magnifications produced by the eyepiece and objective.
`∴M = M_e xx M_0 ...... (1)`
Where, Me and M0 are the magnifying powers of the eyepiece and objective respectively.
If u0 is the distance of the object from the objective and v0 is the distance of the image from the objective, then the magnifying power of the
objective is `M_0 = (h')/h =L/f_0 ( using tanβ = (h/f_0) = =(h/L))`
Where, h, h' are object and image heights respectively and f0 is the focal length of the objective.
L is the tube length i.e. the distance between the second focal point of the objective and the first focal point of the eyepiece.
When the final image is at infinity, `M_e = D/f_e`
Magnifying power of compound microscope,`M = M_0 xx M_e = L/f_0 xx D/f_e`
APPEARS IN
RELATED QUESTIONS
Why must both the objective and the eyepiece of a compound microscope have short focal lengths?
When viewing through a compound microscope, our eyes should be positioned not on the eyepiece but a short distance away from it for best viewing. Why? How much should be that short distance between the eye and eyepiece?
How can the resolving power of a compound microscope be increased? Use relevant formula to support your answer.
Distinguish between myopia and hypermetropia. Show diagrammatically how these defects can be corrected.
A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm. An object is placed at 6 cm from the objective lens. Calculate the magnifying power of the compound microscope. Also calculate the length of the microscope.
Draw a ray diagram to show the working of a compound microscope. Deduce an expression for the total magnification when the final image is formed at the near point.
In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. If the eye piece has a focal length of 5 cm and the final image is formed at the near point, estimate the magnifying power of the microscope.
In which of the following the final image is erect?
(a) Simple microscope
(b) Compound microscope
(c) Astronomical telescope
(d) Galilean telescope
An object is to be seen through a simple microscope of focal length 12 cm. Where should the object be placed so as to produce maximum angular magnification? The least distance for clear vision is 25 cm.
How does the resolving power of a microscope change when
(i) the diameter of the objective lens is decreased?
(ii) the wavelength of the incident light is increased ?
Justify your answer in each case.
With the help of a ray diagram, show how a compound microscope forms a magnified image of a tiny object, at least distance of distinct vision. Hence derive an expression for the magnification produced by it.