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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Draw the graph of y = (x – 1) (x + 3) and hence solve x2 – x – 6 = 0 - Mathematics

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Question

Draw the graph of y = (x – 1) (x + 3) and hence solve x2 – x – 6 = 0

Graph
Sum

Solution

y = (x – 1) (x + 3)

y = x2 + 2x – 3

(i) Draw the graph of y = x2 + 2x – 3 by preparing the table of values given below

x – 4 – 3 – 2 – 1 0 1 2 3 4
x2 16  9 4 1 0 1 4 9 16
2x – 8 – 6 – 4 – 2 0 2 4 6 8
– 3 – 3 – 3 – 3 – 3 – 3 – 3 – 3 – 3 – 3
y 5 0 – 3 – 4 – 3 0 5 12 21

(ii) Plot the points (– 4, 5), (– 3, 0), (– 2, – 3), (– 1, – 4), (0, – 3), (1, 0), (2, 5), (3, 12) and (4, 21) on the graph sheet using suitable scale.

(iii) To solve x2 – x – 6 = 0 subtract x2 – x – 6 = 0 from y = x2 + 2x – 3

(iv) Draw the graph of y = 3x + 3 by preparing the table.

x – 4 – 2 0 2 3 4
y – 9 – 3 3 9 12 15

(v) The straight line cuts the curve at (– 2, – 3) and (3, 12).

Draw perpendicular lines from the point to X-axis.

The line cut the X-axis at – 2 and 3.

The solution set is (– 2, 3)

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Chapter 3: Algebra - Exercise 3.15 [Page 137]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 3 Algebra
Exercise 3.15 | Q 8 | Page 137
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