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Question
Draw the graph of y = (x – 1) (x + 3) and hence solve x2 – x – 6 = 0
Solution
y = (x – 1) (x + 3)
y = x2 + 2x – 3
(i) Draw the graph of y = x2 + 2x – 3 by preparing the table of values given below
x | – 4 | – 3 | – 2 | – 1 | 0 | 1 | 2 | 3 | 4 |
x2 | 16 | 9 | 4 | 1 | 0 | 1 | 4 | 9 | 16 |
2x | – 8 | – 6 | – 4 | – 2 | 0 | 2 | 4 | 6 | 8 |
– 3 | – 3 | – 3 | – 3 | – 3 | – 3 | – 3 | – 3 | – 3 | – 3 |
y | 5 | 0 | – 3 | – 4 | – 3 | 0 | 5 | 12 | 21 |
(ii) Plot the points (– 4, 5), (– 3, 0), (– 2, – 3), (– 1, – 4), (0, – 3), (1, 0), (2, 5), (3, 12) and (4, 21) on the graph sheet using suitable scale.
(iii) To solve x2 – x – 6 = 0 subtract x2 – x – 6 = 0 from y = x2 + 2x – 3
(iv) Draw the graph of y = 3x + 3 by preparing the table.
x | – 4 | – 2 | 0 | 2 | 3 | 4 |
y | – 9 | – 3 | 3 | 9 | 12 | 15 |
(v) The straight line cuts the curve at (– 2, – 3) and (3, 12).
Draw perpendicular lines from the point to X-axis.
The line cut the X-axis at – 2 and 3.
The solution set is (– 2, 3)
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