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Question
Draw the structure of the following compound.
Hex-2-en-4-ynoic acid
Solution 1
\[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - C ≡ C - CH = CH - C - OH}
\end{array}\]
Solution 2
\[\ce{\overset{6}{C}H3 - \overset{5}{C} ≡ \overset{4}{C} - \overset{3}{C}H = \overset{2}{C}H - \overset{1}{C}OOH}\]
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