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Question
Each of the resistors shown in the figure has a resistance of 10 Ω and each of the batteries has an emf of 10 V. Find the currents flowing through the resistors a and bin the two circuits.
Solution
(a) 
From the figure,
Potential difference between the two ends of resistor a = 10 V
Resistance of resistor a =10 Ω
∴ Current through a = \[\frac{10}{10} = 1 A\]
Since the two batteries are connected opposite each other,
potential difference between the terminals of b = 10 – 10 = 0 V
∴ Current through b = 0 A
(b)
From the figure,
Potential difference between the two ends of resistor a = 10 V.
Resistance of resistor a =10 Ω
∴ Current through a = \[\frac{10}{10} = 1 A\]
Since the two batteries are again connected opposite to each other,
Potential difference between terminal of b = 10 – 10 = 0 V
∴ Current through b = 0 A
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