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Question
Energy of an electron in the ground state of the hydrogen atom is −2.18 × 10−18 J. Calculate the ionisation enthalpy of atomic hydrogen in terms of kJ mol−1.
Solution
Energy of an electron in the ground state of the hydrogen atom = −2.18 × 10−18 J
\[\ce{H -> H^+ + e^-}\]
The energy required to ionize 1 mole of hydrogen atoms, we multiply by the Avogadro constant.
E = 2.18 × 10−18 × 6.023 × 1023
= 13.123 × 105 J mol−1
I.E = +1312 K J mol−1
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