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Question
Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
Solution
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
`=(2tan(90^@- 37^@))/(cot37^@)-cot(90^@-10^@)/(tan10^@)`
`=(2cot37^@)/(cot37^@)-tan10^@/(tan10^@)`
= 2 - 1 = 1
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