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Question
Evaluate: (a + bc) (a − bc) (a2 + b2c2)
Sum
Solution
(a + bc) (a − bc) (a2 + b2c2)
= [a2 − (bc)2] (a2 + b2c2) .......[ ∵ (a − b) (a + b) = a2 − b2]
= (a2 − b2c2) (a2 + b2c2)
= (a2)2 − (b2c2)2 .......[ ∵ (a − b) (a + b) = a2 − b2]
= a4 − b4c4
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Product of Sum and Difference of Two Terms
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