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Question
Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
Solution
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
`=cot(90^@-36^@)/(tan36^@)+tan(90^@-70^@)/(cot70^@)-2`
`=tan36^@/(tan36^@)+cot70^@/(cot70^@)-2`
= 1 + 1 - 2 = 0
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