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Question
Solve the differential equation `dy/dx = (x + y+2)/(2(x+y)-1)`
Solution
`dy/dx = ((x+y)+2)/(2(x+y)-1)`
Let `x+y=t`
`1+ dy/dx =dt/dx rArr dy/dx = dt/dx-1`
`dt/dx-1= (t+2)/(2t-1)`
`dt/dx =(t+2)/(2t-1)+1`
`(dt)/dx = (t+2+2t-1)/(2t-1)`
`dt/dx=(3t+1)/(2t-1)`
`((2t-1)/(3t+1))dt = dx`
`2/3 int (6t -3)/(6t+2)dt=int dx`
`2/3 int((6t+2)-5)/((6t+2)) dt = x+C_1`
`2/3 int dt - 10/3 int dt/(6t + 2)=x+C_1`
`2/3t - 5/3 xx(In|3t+ 1|)/3 = x + C`
`2/3t - 5/9 xx(In|3t+ 1|) = x + C`
`2/3(x+y)-5/9In|3(x+y)+1|=x+C`
`2/3(x+y)- 5/9 In|3x +3y +1|=x+C`
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