Advertisements
Advertisements
Question
Let f: R → R be the function defined by f(x) = `1/(2 - cosx)` ∀ x ∈ R.Then, find the range of f
Solution
Given,
f(x) = `1/(2 - cos x)` ∀ x ∈ R
Let y = `1/(2 - cos x)`
2y – ycos x = 1
cos x = `(2y - 1)/y`
cos x = `(2 - 1)/y`
Now, we know that –1 ≤ cos x ≤ 1
So,
–1 ≤ 2 – `1/(y ≤ 1)`
–3 ≤ – `1/(y ≤ -1)`
1 ≤ – `1/(y ≤ 3)`
`1/3` ≤ y ≤ 1
Thus, the range of the given function is `[1/3, 1]`.
APPEARS IN
RELATED QUESTIONS
Evaluate : `int(x1+x^2)/(1+x^4)dx`
Solve the differential equation `dy/dx = (x + y+2)/(2(x+y)-1)`
Evaluate: `int_-6^3 |x+3|dx`
If A, B and C are the elements of Boolean algebra, simplify the expression (A’ + B’) (A + C’) + B’ (B + C). Draw the simplified circuit.
Prove that locus of z is circle and find its centre and radius if is purely imaginary.
For the set A = {1, 2, 3}, define a relation R in the set A as follows: R = {(1, 1), (2, 2), (3, 3), (1, 3)}. Write the ordered pairs to be added to R to make it the smallest equivalence relation.
If R is a relation from a non – empty set A to a non – empty set B, then ____________.
Let A = {a, b, c}, then the range of the relation R = {(a, b), (a, c), (b, c)} defined on A is ____________.
Number of relations that can be defined on the set A = {a, b, c, d} is ____________.
Let R be the relation in the set N given by R = {(a, b) : a = b – 2, b > 6}, then ______.