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Question
Evaluate `lim_(x->0) sinx log x.`
Sum
Solution
Let L = `lim_(x->0) sinx log x.`
L =`lim_(x->0) logx/(cosecx)`
L = `lim_(x->0) (1/x)/(-cosecx cotx)`……………………… (By L hospital)
L = `lim_(x->0)(-sinx tanx)/x`
L =`lim_(x->0)-tanx`
L = O
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nth Derivative of Standard Functions
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