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Question
Evaluate : log2 ( 1 ÷ 8 )
Sum
Solution
Let log2`1/8` = x
⇒ 2x = `1/8`
⇒ 2x = `1/[ 2 xx 2 xx 2 ]`
⇒ 2x = `1/2^3`
⇒ 2x = 2-3
⇒ x = - 3
Thus, log2`1/8` = -3
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Interchanging Logarithmic and Exponential Forms
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