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Chapters
2: Compound Interest (Without using formula)
3: Compound Interest (Using Formula)
4: Expansions (Including Substitution)
5: Factorisation
6: Simultaneous (Linear) Equations (Including Problems)
7: Indices (Exponents)
▶ 8: Logarithms
9: Triangles [Congruency in Triangles]
10: Isosceles Triangles
11: Inequalities
12: Mid-point and Its Converse [ Including Intercept Theorem]
13: Pythagoras Theorem [Proof and Simple Applications with Converse]
14: Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
15: Construction of Polygons (Using ruler and compass only)
16: Area Theorems [Proof and Use]
17: Circle
18: Statistics
19: Mean and Median (For Ungrouped Data Only)
20: Area and Perimeter of Plane Figures
21: Solids [Surface Area and Volume of 3-D Solids]
22: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
24: Solution of Right Triangles [Simple 2-D Problems Involving One Right-angled Triangle]
25: Complementary Angles
26: Co-ordinate Geometry
27: Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
28: Distance Formula
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Solutions for Chapter 8: Logarithms
Below listed, you can find solutions for Chapter 8 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 8 Logarithms Exercise 8 (A) [Pages 103 - 104]
Express the following in logarithmic form : 53 = 125
Express the following in logarithmic form :
3-2 = `1/9`
Express the following in logarithmic form :
10-3 = 0.001
Express the following in logarithmic form : `(81)^(3/4) = 27`
Express the following in exponential form : log80.125 = -1
Express the following in exponential form :
log100.01 = - 2
Express the following in exponential form : logaA = x
Express the following in exponential form : log101 = 0
Solve for x : log10 x = -2.
Find the logarithm of : 100 to the base 10
Find the logarithm of : 0.1 to the base 10
Find the logarithm of : 0.001 to the base 10
Find the logarithm of : 32 to the base 4
Find the logarithm of : 0.125 to the base 2
Find the logarithm of : `1/16` to the base 4
Find the logarithm of : 27 to the base 9
Find the logarithm of : `1/81` to the base 27
State, true or false : If log10 x = a, then 10x = a.
State, true or false : If xy = z, then y = logzx .
State, true or false : log2 8 = 3 and log8 = 2 = `1/3`
Find x, if : log3 x = 0
Find x, if : logx 2 = - 1.
Find x, if : log9243 = x
Find x, if : log5 (x - 7) = 1
Find x, if : log432 = x - 4
Find x, if : log7 (2x2 - 1) = 2
Evaluate : log10 0.01
Evaluate : log2 ( 1 ÷ 8 )
Evaluate : log5 1
Evaluate : log5 125
Evaluate : log16 8
Evaluate : log0.5 16
If loga m = n, express an - 1 in terms of a and m.
Given log2 x = m. Express 2m - 3 in terms of x.
Given log5 y = n. Express 53n + 2 in terms of y.
If log2x = a and log3 y = a, write 72a in terms of x and y.
Solve for x:
log(x - 1) + log (x + 1) = log21
If log (x2 - 21) = 2, show that x = ± 11.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 8 Logarithms Exercise 8 (B) [Pages 106 - 107]
Express in terms of log 2 and log 3 : log 36
Express in terms of log 2 and log 3:
log 144
Express in terms of log 2 and log 3 : log 4.5
Express in terms of log 2 and log 3 :
`"log"26/51 - "log"91/119`
Express in terms of log 2 and log 3 :
`"log"75/16 - 2"log"5/9 + "log"32/243`
Express the following in a form free from logarithm:
2 log x - log y = 1
Express the following in a form free from logarithm:
2 log x + 3 log y = log a
Express the following in a form free from logarithm:
a log x - b log y = 2 log 3
Evaluate the following without using tables :
log 5 + log 8 - 2 log 2
Evaluate the following without using tables :
log 4 + `1/3` log 125 - `1/5`log 32
Evaluate the following without using tables :
log108 + log1025 + 2 log103 - log1018
Prove that : `2"log" 15/18 - "log"25/162 + "log"4/9 = log 2 `
Find x, if : x - log 48 + 3 log 2 = `1/3`log 125 - log 3.
Express log102 + 1 in the form of log10x .
Solve for x : log10 (x - 10) = 1
Solve for x : log (x2 - 21) = 2.
Solve for x : log (x - 2) + log (x + 2) = log 5
Solve for x : log (x + 5) + log (x - 5) = 4 log 2 + 2 log 3
Solve for x : `(log 81)/(log27 )` = x
Solve for x : ` ( log 128) / ( log 32 ) ` = x
Solve for x : ` (log 64)/(log 8)` = log x
Solve for x :
`log 225/log15` = log x
Given that log x = m + n and log y = m - n, express the value of log ` ( 10x ) / ( y ^ 2 )` in terms of m and n.
State, true or false : log 1 x log 1000 = 0
State, true or false :
`log x/log y` = log x - log y
State, true or false :
If `log 25/log 5 = log x`, then x = 2.
State, true or false :
log x x log y = log x + log y
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b': log 12
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b': log 2.25
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b': log `2 1/4`
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b' : log 5.4
If log102 = a and log103 = b; express each of the following in terms of 'a' and 'b' : log 60
If log102 = a and log103 = b; express each of the following in terms of 'a' and 'b' : log `3 1/8`
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 12
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 1.2
If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 3.6
If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 15
If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 25
If log 2 = 0.3010 and log 3 = 0.4771; find the value of:
`2/3` log 8
Given 2 log10 x + 1 = log10 250, find :
(i) x
(ii) log10 2x
Given 3log x + `1/2`log y = 2, express y in term of x.
If x = (100)a , y = (10000)b and z = (10)c , find log`(10sqrty)/( x^2z^3)` in terms of a, b and c.
If 3( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log x, find x.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 8 Logarithms Exercise 8 (C) [Page 108]
If log10 8 = 0.90; find the value of : log10 4
If log10 8 = 0.90; find the value of : log√32
If log10 8 = 0.90; find the value of : log 0.125
If log 27 = 1.431, find the value of : log 9
If log 27 = 1.431, find the value of : log 300
If log10 a = b, find 103b - 2 in terms of a.
If log5 x = y, find 52y+ 3 in terms of x.
Given: log3 m = x and log3 n = y.
Express 32x - 3 in terms of m.
Given: log3 m = x and log3 n = y.
Write down `3^(1 - 2y + 3x)` in terms of m and n.
Given: log3 m = x and log3 n = y.
If 2 log3 A = 5x - 3y; find A in terms of m and n.
Simplify : log (a)3 - log a
Simplify : log (a)3 ÷ log a
If log (a + b) = log a + log b, find a in terms of b.
Prove that : (log a)2 - (log b)2 = log `(( a )/( b ))` . Log (ab)
Prove that : If a log b + b log a - 1 = 0, then ba. ab = 10
If log (a + 1) = log (4a - 3) - log 3; find a.
If 2 log y - log x - 3 = 0, express x in terms of y.
Prove that:
log10 125 = 3(1 - log102).
Given log x = 2m - n , log y = n - 2m and log z = 3m - 2n , find in terms of m and n, the value of log `(x^2y^3 ) /(z^4) `.
Given `log_x 25 - log_x 5 = 2 - log_x (1/125)` ; find x.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 8 Logarithms Exercise 8 (D) [Pages 110 - 111]
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
If a2 = log x, b3 = log y and 3a2 - 2b3 = 6 log z, express y in terms of x and z .
If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a2 + b2 = 6ab.
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
If m = log 20 and n = log 25, find the value of x, so that :
2 log (x - 4) = 2 m - n.
Solve for x and y ; if x > 0 and y > 0 ; log xy = log `x/y` + 2 log 2 = 2.
Find x, if : logx 625 = - 4
Find x, if : logx (5x - 6) = 2
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
If p = log 20 and q = log 25 , find the value of x , if 2log( x + 1 ) = 2p - q.
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
Given log10x = 2a and log10y = `b/2`. Write 102b + 1 in terms of y.
Given log10x = 2a and log10y = `b/2. "If" log_10^p = 3a - 2b`, express P in terms of x and y.
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Solve for x, if : logx49 - logx7 + logx `1/343` + 2 = 0
If a2 = log x , b3 = log y and `a^2/2 - b^3/3` = log c , find c in terms of x and y.
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Evaluate: logb a × logc b × loga c.
Evaluate : log38 ÷ log916
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Show that : loga m ÷ logab m + 1 + log ab
If log√27x = 2 `(2)/(3)` , find x.
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
Solutions for 8: Logarithms
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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 8 - Logarithms
Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE 8 (Logarithms) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 8 Logarithms are Introduction of Logarithms, Interchanging Logarithmic and Exponential Forms, Laws of Logarithm, Expansion of Expressions with the Help of Laws of Logarithm, More About Logarithm, Logarithmic to Exponential, Exponential to Logarithmic, Quotient Law, Power Law, Product Law.
Using Selina Concise Mathematics [English] Class 9 ICSE solutions Logarithms exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 9 ICSE students prefer Selina Textbook Solutions to score more in exams.
Get the free view of Chapter 8, Logarithms Concise Mathematics [English] Class 9 ICSE additional questions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.