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Chapters
2: Compound Interest (Without using formula)
3: Compound Interest (Using Formula)
4: Expansions (Including Substitution)
5: Factorisation
6: Simultaneous (Linear) Equations (Including Problems)
7: Indices (Exponents)
8: Logarithms
9: Triangles [Congruency in Triangles]
10: Isosceles Triangles
11: Inequalities
12: Mid-point and Its Converse [ Including Intercept Theorem]
13: Pythagoras Theorem [Proof and Simple Applications with Converse]
14: Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
15: Construction of Polygons (Using ruler and compass only)
16: Area Theorems [Proof and Use]
17: Circle
18: Statistics
19: Mean and Median (For Ungrouped Data Only)
20: Area and Perimeter of Plane Figures
21: Solids [Surface Area and Volume of 3-D Solids]
22: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
24: Solution of Right Triangles [Simple 2-D Problems Involving One Right-angled Triangle]
25: Complementary Angles
26: Co-ordinate Geometry
▶ 27: Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
28: Distance Formula
![Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 27 - Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 27 - Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) - Shaalaa.com](/images/concise-mathematics-english-class-9-icse_6:b313c06da7fb4b0f885a06c3b5e4e4fa.jpg)
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Solutions for Chapter 27: Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
Below listed, you can find solutions for Chapter 27 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.
Selina solutions for Concise Mathematics [English] Class 9 ICSE 27 Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) Exercise 27 (A) [Page 326]
Draw the graph for the equation, given below :
x = 5
Draw the graph for the equation, given below :
x + 5 = 0
Draw the graph for the equation, given below :
y = 7
Draw the graph for the equation, given below :
y + 7 = 0
Draw the graph for the equation, given below :
2x + 3y = 0
Draw the graph for the equation, given below :
3x + 2y = 6
Draw the graph for the equation, given below :
x - 5y + 4 = 0
Draw the graph for the equation, given below :
5x + y + 5 = 0
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(1)/(3) x +(1)/(5) y = 1`.
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(2x + 15)/(3) = y - 1`
Draw the graph of the straight line given by the equation 4x - 3y + 36 = 0
Calculate the area of the triangle formed by the line drawn and the co-ordinate axes.
Draw the graph of the equation 2x - 3y - 5 = 0
From the graph, find:
(i) x1, the value of x, when y = 7
(ii) x2, the value of x, when y = - 5.
Draw the graph of the equation
4x + 3y + 6 = 0
From the graph, find :
(i) y1, the value of y, when x = 12.
(ii) y2, the value of y, when x = - 6.
Use the table given below to draw the graph.
X | - 5 | - 1 | 3 | b | 13 |
Y | - 2 | a | 2 | 5 | 7 |
From your graph, find the values of 'a' and 'b'.
State a linear relationship between the variables x and y.
Draw the graph obtained from the table below:
X | a | 3 | - 5 | 5 | c | - 1 |
Y | - 1 | 2 | b | 3 | 4 | 0 |
Use the graph to find the values of a, b and c. State a linear relation between the variables x and y.
A straight line passes through the points (2, 4) and (5, - 2). Taking 1 cm = 1 unit; mark these points on a graph paper and draw the straight line through these points. If points (m, - 4) and (3, n) lie on the line drawn; find the values of m and n.
Draw the graph (straight line) given by equation x - 3y = 18. If the straight line is drawn passes through the points (m, - 5) and (6, n); find the values of m and n.
Use the graphical method to find the value of k, if:
(k, -3) lies on the straight line 2x + 3y = 1
Use the graphical method to find the value of k, if:
(5, k - 2) lies on the straight line x - 2y + 1 = 0
Selina solutions for Concise Mathematics [English] Class 9 ICSE 27 Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) Exercise 27 (B) [Page 329]
Solve, graphically, the following pairs of equation :
x - 5 = 0
y + 4 = 0
Solve, graphically, the following pairs of equation :
2x + y = 23
4x - y = 19
Solve, graphically, the following pairs of equation :
3x + 7y = 27
8 - y = `(5)/(2)x`
Solve, graphically, the following pairs of equations :
`(x + 1)/(4) = (2)/(3)(1 - 2y)`
`(2 + 5y)/(3) = x/(7) -2`
Solve graphically the simultaneous equations given below. Take the scale as 2 cm = 1 unit on both the axes.
x - 2y - 4 = 0
2x + y = 3
Use graph paper for this question. Draw the graph of 2x - y - 1 = 0 and 2x + y = 9 on the same axes. Use 2 cm = 1 unit on both axes and plot only 3 points per line. Write down the coordinates of the point of intersection of the two lines.
Use graph paper for this question. Take 2 cm = 2 units on x-axis and 2 cm = 1 unit on y-axis.
Solve graphically the following equation:
3x + 5y = 12; 3x - 5y + 18 = 0 (Plot only three points per line)
Use graph paper for this question. Take 2 cm = 1 unit on both the axes.
- Draw the graphs of x + y + 3 = 0 and 3x - 2y + 4 = 0. Plot only three points per line.
- Write down the coordinates of the point of intersection of the lines.
- Measure and record the distance of the point of intersection of the lines from the origin in cm.
The sides of a triangle are given by the equations y - 2 = 0; y + 1 = 3 (x - 2) and x + 2y = 0.
Find, graphically :
(i) the area of a triangle;
(ii) the coordinates of the vertices of the triangle.
By drawing a graph for each of the equations 3x + y + 5 = 0; 3y - x = 5 and 2x + 5y = 1 on the same graph paper; show that the lines given by these equations are concurrent (i.e. they pass through the same point). Take 2 cm = 1 unit on both the axes.
Using a scale of 1 cm to 1 unit for both the axes, draw the graphs of the following equations: 6y = 5x + 10, y = 5x - 15.
From the graph find :
(i) the coordinates of the point where the two lines intersect;
(ii) the area of the triangle between the lines and the x-axis.
The cost of manufacturing x articles is Rs. (50 + 3x). The selling price of x articles is Rs. 4x.
On a graph sheet, with the same axes, and taking suitable scales draw two graphs, first for the cost of manufacturing against no. of articles and the second for the selling price against the number of articles.
Use your graph to determine:
No. of articles to be manufactured and sold to break even (no profit and no loss).
The cost of manufacturing x articles is Rs.(50 + 3x). The selling price of x articles is Rs. 4x.
On a graph sheet, with the same axes, and taking suitable scales draw two graphs, first for the cost of manufacturing against no. of articles and the second for the selling price against the number of articles.
Use your graph to determine:
The profit or loss made when (a) 30 (b) 60 articles are manufactured and sold.
Find graphically, the vertices of the triangle whose sides have the equations 2y - x = 8; 5y - x = 14 and y - 2x = 1 respectively. Take 1 cm = 1 unit on both the axes.
Using the same axes of co-ordinates and the same unit, solve graphically :
x + y = 0 and 3x - 2y = 10.
(Take at least 3 points for each line drawn).
Solve graphically, the following equations.
x + 2y = 4; 3x - 2y = 4.
Take 2 cm = 1 unit on each axis.
Also, find the area of the triangle formed by the lines and the x-axis.
Use the graphical method to find the value of 'x' for which the expressions `(3x + 2)/(2) and (3)/(4)x - 2`
The course of an enemy submarine, as plotted on rectangular co-ordinate axes, gives the equation 2x + 3y = 4. On the same axes, a destroyer's course is indicated by the graph x - y = 7. Use the graphical method to find the point at which the paths of the submarine and the destroyer intersect?
Solutions for 27: Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
![Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 27 - Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 27 - Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) - Shaalaa.com](/images/concise-mathematics-english-class-9-icse_6:b313c06da7fb4b0f885a06c3b5e4e4fa.jpg)
Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 27 - Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
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Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 27 Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) are Graphical Method, Graph of a Linear Equation in Two Variables.
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