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Question
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(1)/(3) x +(1)/(5) y = 1`.
Solution
`(1)/(3) x +(1)/(5) y = 1`
⇒ `(5x + 3y)/(15) = 1`
⇒ 5x + 3y = 15
⇒ 3y = 15 - 5x
⇒ y = `(15 - 5x)/(3)`
When x = 0; y = `(15 - 5 xx 0)/(3) = (15 - 0)/(3)` = 5
When x = 3; y = `(15 - 5 xx 3)/(3) = (15 - 15)/(3)` = 0
When x = -3; y = `(15 - 5 xx (-3))/(3) = (15 + 15)/(3)` = 10
| X | 0 | 3 | - 3 |
| Y | 5 | 0 | 10 |
Plotting these points we get the required graph as shown below:
From the figure it is clear that, the graph meets the coordinate axes at (3,0) and (0,5).
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