English

Draw the Graph for Each Equation, Given Below : X + 5 = 0 - Mathematics

Advertisements
Advertisements

Question

Draw the graph for the equation, given below :
x + 5 = 0

Graph

Solution

x + 5 = 0
x = - 5
The graph x = - 5 in the following figure is a straight line AB which is parallel to y-axis at a distance of 5 units from it in the negative x-direction.

shaalaa.com
  Is there an error in this question or solution?
Chapter 27: Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) - Exercise 27 (A) [Page 326]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 27 Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
Exercise 27 (A) | Q 1.2 | Page 326

RELATED QUESTIONS

If the work done by a body on application of a constant force is directly proportional to the distance travelled by the body, express this in the form of an equation in two variables and draw the graph of the same by taking the constant force as 5 units. Also read from the graph the work done when the distance travelled by the body is

(i) 2 units (ii) 0 unit


Yamini and Fatima, two students of Class IX of a school, together contributed Rs. 100 towards the Prime Minister’s Relief Fund to help the earthquake victims. Write a linear equation which satisfies this data. (You may take their contributions as Rs. x and Rs. y.) Draw the graph of the same.


Draw the graph for the equation, given below :
3x + 2y = 6


Use the graphical method to find the value of k, if:
(k, -3) lies on the straight line 2x + 3y = 1


Use graph paper for this question. Take 2 cm = 2 units on x-axis and 2 cm = 1 unit on y-axis.
Solve graphically the following equation:
3x + 5y = 12; 3x - 5y + 18 = 0 (Plot only three points per line)


Draw the graphs of the following linear equations:
y + 5 = 0


Draw the graphs of the following linear equations:
5x - 5y = 8


The point (0, 3) lies on the graph of the linear equation 3x + 4y = 12.


The graph of the linear equation x + 2y = 7 passes through the point (0, 7).


The force exerted to pull a cart is directly proportional to the acceleration produced in the body. Express the statement as a linear equation of two variables and draw the graph of the same by taking the constant mass equal to 6 kg. Read from the graph, the force required when the acceleration produced is (i) 5 m/sec2, (ii) 6 m/sec2.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×
Our website is made possible by ad-free subscriptions or displaying online advertisements to our visitors.
If you don't like ads you can support us by buying an ad-free subscription or please consider supporting us by disabling your ad blocker. Thank you.