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Question
Evaluate : log0.5 16
Sum
Solution
Let log0.5 16 = x
⇒ 0.5x = 16
⇒ `(5/10)^x = 2 xx 2 xx 2 xx 2`
⇒ `(1/2)^x = 2^4`
⇒ `1/2^x = 2^4`
⇒ 2- x = 24
⇒ - x = 4
⇒ x = - 4
Thus, log0.516 = - 4
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Interchanging Logarithmic and Exponential Forms
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