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Question
Evaluate : log5 125
Sum
Solution
Let log5 125 = x
⇒ 5x = 125
⇒ 5x = 5 x 5 x 5
⇒ 5x = 53
⇒ x = 3
Thus, log5125 = 3
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Interchanging Logarithmic and Exponential Forms
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