Question

Given log₂ x = m. Express 2^{m - 3}  in terms of x.

Answer 1

log₂x  = m

⇒ 2^m = x 
Consider 2^m  = x

⇒ ${\displaystyle \frac{2^m}{2^3}=\frac{x}{2^3}}$

⇒ ${\displaystyle 2^{m-3}=\frac{x}{8}}$