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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 6 - Simultaneous (Linear) Equations (Including Problems) [Latest edition]

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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 6 - Simultaneous (Linear) Equations (Including Problems) - Shaalaa.com
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Solutions for Chapter 6: Simultaneous (Linear) Equations (Including Problems)

Below listed, you can find solutions for Chapter 6 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.


Exercise 6 (A)Exercise 6 (B)Exercise 6 (C)Exercise 6 (D)Exercise 6 (E)Exercise 6 (F)Exercise 6 (G)
Exercise 6 (A) [Page 79]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (A) [Page 79]

Exercise 6 (A) | Q 1 | Page 79

Solve the pair of linear (simultaneous) equation by the method of elimination by substitution :
8x + 5y = 9
3x + 2y = 4

Exercise 6 (A) | Q 2 | Page 79

Solve the pair of linear (simultaneous) equation by the method of elimination by substitution :
2x - 3y = 7
5x + y= 9

Exercise 6 (A) | Q 3 | Page 79

Solve the pair of linear (simultaneous) equation by the method of elimination by substitution:
2x + 3y = 8
2x = 2 + 3y

Exercise 6 (A) | Q 4 | Page 79

Solve the following pair of linear (simultaneous) equation by the method of elimination by substitution:

0.2x + 0.1y = 25

2(x - 2) - 1.6y = 116

Exercise 6 (A) | Q 5 | Page 79

Solve the pair of linear (simultaneous) equation by the method of elimination by substitution:
6x = 7y + 7
7y - x = 8

Exercise 6 (A) | Q 6 | Page 79

Solve the pair of linear (simultaneous) equation by the method of elimination by substitution :
y = 4x - 7
16x - 5y = 25

Exercise 6 (A) | Q 7 | Page 79

Solve the pair of linear (simultaneous) equation by the method of elimination by substitution:
2x + 7y = 39
3x + 5y = 31

Exercise 6 (A) | Q 8 | Page 79

Solve the following pair of linear (simultaneous) equation by the method of elimination by substitution:

1.5x + 0.1y = 6.2

3x - 0.4y = 11.2

Exercise 6 (A) | Q 9 | Page 79

Solve the following pair of linear (Simultaneous ) equation using method of elimination by substitution :
2( x - 3 ) + 3( y - 5 ) = 0
5( x - 1 ) + 4( y - 4 ) = 0

Exercise 6 (A) | Q 10 | Page 79

Solve th following pair of linear (Simultaneous ) equation using method of elimination by substitution :
`[ 2x + 1]/7 + [5y - 3]/3 = 12`

`[3x + 2 ]/2 - [4y + 3]/9 = 13`   

Exercise 6 (A) | Q 11 | Page 79

Solve the following pair of linear (simultaneous) equation using method of elimination by substitution:
3x + 2y =11
2x - 3y + 10 = 0

Exercise 6 (A) | Q 12 | Page 79

Solve the following pair of linear (simultaneous) equation using method of elimination by substitution :
2x - 3y + 6 = 0
2x + 3y - 18 = 0

Exercise 6 (A) | Q 13 | Page 79

Solve the following pair of linear (simultaneous) equation using method of elimination by substitution:

`[3x]/2 - [5y]/3 + 2 = 0`

`x/3 + y/2 = 2 1/6`

Exercise 6 (A) | Q 14 | Page 79

Solve the following pairs of linear (simultaneous) equation using method of elimination by substitution:
`x/6 + y/15 = 4`

`x/3 - y/12 = 4 3/4` 

Exercise 6 (B) [Page 81]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (B) [Page 81]

Exercise 6 (B) | Q 1 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
13 + 2y = 9x
3y = 7x

 

Exercise 6 (B) | Q 2 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
3x - y = 23
`x/3 + y/4 = 4`

Exercise 6 (B) | Q 3 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`[5y]/2 - x/3 = 8`

`y/2 + [5x]/3 = 12`

Exercise 6 (B) | Q 4 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`1/5( x - 2 ) = 1/4( 1 - y )`
26x + 3y + 4 = 0

Exercise 6 (B) | Q 5 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients:

y = 2x - 6; y = 0

Exercise 6 (B) | Q 6 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`[ x - y ]/6 = 2( 4 - x )`
2x + y = 3( x - 4 )

Exercise 6 (B) | Q 7 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
3 - (x - 5) = y + 2
2 (x + y) = 4 - 3y

Exercise 6 (B) | Q 8 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
2x - 3y - 3 = 0
`[2x]/3 + 4y + 1/2` = 0

Exercise 6 (B) | Q 9 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
13x+ 11y = 70
11x + 13y = 74

Exercise 6 (B) | Q 10 | Page 81

For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
41x + 53y = 135
53x + 41y = 147

Exercise 6 (B) | Q 11 | Page 81

If 2x + y = 23 and 4x - y = 19; find the values of x - 3y and 5y - 2x.

Exercise 6 (B) | Q 12 | Page 81

If 10y = 7x - 4 and 12x + 18y = 1; find the values of 4x + 6y and 8y - x.

Exercise 6 (B) | Q 13.1 | Page 81

Solve for x and y : 
`[ y + 7 ]/5 = [ 2y - x ]/4 + 3x - 5`

`[ 7 - 5x ]/2 + [ 3 - 4y ]/6 = 5y - 18`

Exercise 6 (B) | Q 13.2 | Page 81

Solve for x and y:

4x = 17 - `[ x - y ]/8`

2y + x = 2 + `[ 5y + 2 ]/3`

Exercise 6 (B) | Q 14 | Page 81

Find the value of m, if x = 2, y = 1 is a solution of the equation 2x + 3y = m.

Exercise 6 (B) | Q 15 | Page 81

10% of x + 20% of y = 24
3x - y = 20

Exercise 6 (B) | Q 16 | Page 81

The value of expression mx - ny is 3 when x = 5 and y = 6. And its value is 8 when x = 6 and y = 5. Find the values of m and n.

Exercise 6 (B) | Q 17 | Page 81

Solve :
11(x - 5) + 10(y - 2) + 54 = 0
7(2x - 1) + 9(3y - 1) = 25

Exercise 6 (B) | Q 18 | Page 81

Solve :
`[ 7 + x ]/5 - [ 2x - y ]/4 = 3y - 5`

`[5y - 7]/2 + [ 4x - 3 ]/6 = 18 - 5x`

Exercise 6 (B) | Q 19 | Page 81

Solve :
`4x + [ x - y ]/8 = 17`

`2y + x - [ 5y + 2 ]/3 = 2`

Exercise 6 (C) [Page 85]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (C) [Page 85]

Exercise 6 (C) | Q 1 | Page 85

Solve, using cross-multiplication :
4x + 3y = 17
3x - 4y + 6 = 0

Exercise 6 (C) | Q 2 | Page 85

Solve, using cross-multiplication :
3x + 4y = 11
2x + 3y = 8

Exercise 6 (C) | Q 3 | Page 85

Solve, using cross-multiplication :
6x + 7y - 11 = 0
5x + 2y = 13

Exercise 6 (C) | Q 4 | Page 85

Solve, using cross-multiplication :
5x + 4y + 14 = 0
3x = -10 - 4y

Exercise 6 (C) | Q 5 | Page 85

Solve, using cross-multiplication :
x - y + 2 = 0
7x + 9y = 130

Exercise 6 (C) | Q 6 | Page 85

Solve, using cross-multiplication :
4x - y = 5
5y - 4x = 7

Exercise 6 (C) | Q 7 | Page 85

Solve, using cross-multiplication :
4x - 3y = 0
2x + 3y = 18

Exercise 6 (C) | Q 8 | Page 85

Solve, using cross-multiplication :
8x + 5y = 9
3x + 2y = 4

Exercise 6 (C) | Q 9 | Page 85

Solve, using cross-multiplication :
4x - 3y - 11 = 0
6x + 7y - 5 = 0

Exercise 6 (C) | Q 10 | Page 85

Solve, using cross-multiplication :
4x + 6y = 15
3x - 4y = 7

Exercise 6 (C) | Q 11 | Page 85

Solve, using cross-multiplication :
0.4x - 1.5y = 6.5
0.3x + 0.2y = 0.9

Exercise 6 (C) | Q 12 | Page 85

Solve, using cross-multiplication :
√2x - √3y = 0
√5x + √2y = 0

Exercise 6 (D) [Pages 87 - 88]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (D) [Pages 87 - 88]

Exercise 6 (D) | Q 1 | Page 87

Solve :
`9/x - 4/y = 8`

`13/x + 7/y = 101`

Exercise 6 (D) | Q 2 | Page 87

Solve the pairs of equations :
`3/x + 2/y = 10`

`9/x - 7/y = 10.5`

Exercise 6 (D) | Q 3 | Page 87

Solve :
5x + `8/y` = 19

3x - `4/y` = 7

Exercise 6 (D) | Q 4 | Page 87

Solve :
4x + `6/y` = 15 and 3x - `4/y` = 7. Hence, find a if y = ax - 2.

Exercise 6 (D) | Q 5 | Page 88

Solve :
`3/x - 2/y = 0 and 2/x + 5/y = 19` Hence, find 'a' if y = ax + 3.

Exercise 6 (D) | Q 6.1 | Page 88

Solve :
`20/[ x + y ] + 3/[ x - y ] = 7`

`8/[ x - y ] - 15/[ x + y ] = 5`

Exercise 6 (D) | Q 6.2 | Page 88

Solve : 
`34/[ 3x + 4y ] + 15/[ 3x - 2y ] = 5`

`25/[ 3x - 2y ] - 8.50/[ 3x + 4y ] = 4.5`

Exercise 6 (D) | Q 7.1 | Page 88

Solve:

x + y = 2xy

x - y = 6xy

Exercise 6 (D) | Q 7.2 | Page 88

Solve :
x+ y = 7xy
2x - 3y = - xy

Exercise 6 (D) | Q 8 | Page 88

Solve :
`a/x - b/y = 0`

`(ab^2)/x + (a^2b)/y = a^2 + b^2`

Exercise 6 (D) | Q 9 | Page 88

Solve : 
`[2xy]/[ x + y ] = 3/2`

`[xy]/[ 2x - y ] = -3/10`
x + y ≠ 0 and 2x - y ≠ 0 

Exercise 6 (D) | Q 10 | Page 88

Solve :
`3/(2x) + 2/(3y) = -1/3`

`3/(4x) + 1/(2y) = -1/8`

Exercise 6 (E) [Page 90]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (E) [Page 90]

Exercise 6 (E) | Q 1 | Page 90

The ratio of two numbers is `2/3`. If 2 is subtracted from the first and 8 from the second, the ratio becomes the reciprocal of the original ratio. Find the numbers.

Exercise 6 (E) | Q 2 | Page 90

Two numbers are in the ratio 4 : 7. If thrice the larger be added to twice the smaller, the sum is 59. Find the numbers.

Exercise 6 (E) | Q 3 | Page 90

When the greater of the two numbers increased by 1divides the sum of the numbers, the result is `3/2`. When the difference of these numbers is divided by the smaller, the result `1/2`. Find the numbers.

Exercise 6 (E) | Q 4 | Page 90

The sum of two positive numbers x and y (x > y) is 50 and the difference of their squares is 720. Find the numbers.

Exercise 6 (E) | Q 5 | Page 90

The sum of two numbers is 8 and the difference of their squares is 32. Find the numbers.

Exercise 6 (E) | Q 6 | Page 90

The difference between two positive numbers x and y (x > y) is 4 and the difference between their reciprocals is `4/21`. Find the numbers.

Exercise 6 (E) | Q 7 | Page 90

Two numbers are in the ratio 4:5. If 30 is subtracted from each of the numbers, the ratio becomes 1:2. Find the numbers.

Exercise 6 (E) | Q 8 | Page 90

If the numerator of a fraction is increased by 2 and denominator is decreased by 1, it becomes `2/3`. If the numerator is increased by 1 and denominator is increased by 2, it becomes `1/3`. Find the fraction.

Exercise 6 (E) | Q 9 | Page 90

The sum of the numerator and the denominator of a fraction is equal to 7. Four times the numerator is 8 less than 5 times the denominator. Find the fraction.

Exercise 6 (E) | Q 10 | Page 90

lf the numerator of a fraction is multiplied by 2 and its denominator is increased by 1, it becomes 1. However, if the numerator is increased by 4 and denominator is multiplied by 2, the fraction becomes `1/2`. Find the fraction.

Exercise 6 (E) | Q 11 | Page 90

A Fraction becomes `1/2` if 5 subtracted from its numerator and 3 is subtracted from its denominator. If the denominator of this fraction is 5 more than its numerator. Find the fraction.

Exercise 6 (E) | Q 12 | Page 90

The sum of the digits of the digits of two digit number is 5. If the digits are reversed, the number is reduced by 27. Find the number.

Exercise 6 (E) | Q 13 | Page 90

The sum of the digits of a two digit number is 7. If the digits are reversed, the new number decreased by 2, equals twice the original number. Find the number.

Exercise 6 (E) | Q 14 | Page 90

The ten’s digit of a two digit number is three times the unit digit. The sum of the number and the unit digit is 32. Find the number.

Exercise 6 (E) | Q 15 | Page 90

A two-digit number is such that the ten’s digit exceeds twice the unit’s digit by 2 and the number obtained by inter-changing the digits is 5 more than three times the sum of the digits. Find the two digit number.

Exercise 6 (E) | Q 16 | Page 90

Four times a certain two digit number is seven times the number obtained on interchanging its digits. If the difference between the digits is 4; find the number.

Exercise 6 (E) | Q 17 | Page 90

The sum of two digit number and the number obtained by interchanging the digits of the number is 121. If the digits of the number differ by 3, find the number.

Exercise 6 (E) | Q 18 | Page 90

A two digit number is obtained by multiplying the sum of the digits by 8. Also, it is obtained by multiplying the difference of the digits by 14 and adding 2. Find the number.

Exercise 6 (F) [Page 92]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (F) [Page 92]

Exercise 6 (F) | Q 1 | Page 92

Five years ago, A's age was four times the age of B. Five years hence, A’s age will be twice the age of B. Find their preset ages.

Exercise 6 (F) | Q 2 | Page 92

A is 20 years older than B. 5 years ago, A was 3 times as old as B. Find their present ages.

Exercise 6 (F) | Q 3 | Page 92

Four years ago, a mother was four times as old as her daughter. Six years later, the mother will be two and a half times as old as her daughter at that time. Find the present ages of the mother and her daughter.

Exercise 6 (F) | Q 4 | Page 92

The age of a man is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children at that time. Find the present age of the man.

Exercise 6 (F) | Q 5 | Page 92

The annual incomes of A and B are in the ratio 3 : 4 and their annual expenditure are in the ratio 5 : 7. If each Rs. 5000; find their annual incomes.

Exercise 6 (F) | Q 6 | Page 92

In an examination, the ratio of passes to failures was 4 : 1. Had 30 less appeared and 20 less passed, the ratio of passes to failures would have been 5 : 1. Find the number of students who appeared for the examination.

Exercise 6 (F) | Q 7 | Page 92

A and B both the have some pencils. If A gives 10 pencils to B, then B will have twice as many as A. And if B gives 10 pencils to A, then they will have the same number of pencils. How many pencils does each have ?

Exercise 6 (F) | Q 8 | Page 92

1250 persons went to sea a circus-show. Each adult paid Rs. 75 and each child paid Rs. 25 for the admission ticket. Find the number of adults and number of children, if the total collection from them amounts to Rs. 61,250.

Exercise 6 (F) | Q 9 | Page 92

Two articles A and B are sold for Rs. 1,167 making 5% profit on A and 7% profiton A and 7% profit on B. IF the two articles are sold for Rs. 1,165, a profit of 7% is made on A and a profit of 5% is made on B. Find the cost prices of each article.

Exercise 6 (F) | Q 10 | Page 92

Pooja and Ritu can do a piece of work in `17 1/7` days. If one day work of Pooja be three fourth of one day work of Ritu’ find in how many days each will do the work alone.

Exercise 6 (G) [Page 94]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 6 Simultaneous (Linear) Equations (Including Problems) Exercise 6 (G) [Page 94]

Exercise 6 (G) | Q 1 | Page 94

Rohit says to Ajay, “Give me hundred, I shall then become twice as rich as you.” Ajay replies, “if you give me ten, I shall be six times as rich as you.” How much does each have originally ?

Exercise 6 (G) | Q 2 | Page 94

The sum of a two digit number and the number obtained by reversing the order of the digits is 99. Find the number, if the digits differ by 3.

Exercise 6 (G) | Q 3 | Page 94

Seven times a two digit number is equal to four times the number obtained by reversing the digits. If the difference between the digits is 3 find the number.

Exercise 6 (G) | Q 4 | Page 94

From Delhi station, if we buy 2 tickets for station A and 3 tickets for station B, the total cost is Rs. 77. But if we buy 3 tickets for station A and 5 tickets for station B, the total cost is Rs. 124. What are the fares from Delhi to station A and to station B ?

Exercise 6 (G) | Q 5 | Page 94

The sum of digit of a two digit number is 11. If the digit at ten's place is increased by 5 and the digit at unit place is decreased by 5, the digits of the number are found to be reversed. Find the original number.

Exercise 6 (G) | Q 6 | Page 94

90% acid solution (90% pure acid and 10% water) and 97% acid solution are mixed to obtain 21 litres of 95% acid solution. How many litres of each solution are mixed.

Exercise 6 (G) | Q 7 | Page 94

The class XI students of school wanted to give a farewell party to the outgoing students of class XII. They decided to purchase two kinds of sweets, one costing Rs. 250 per kg and other costing Rs. 350 per kg. They estimated that 40 kg of sweets were needed. If the total budget for the sweets was Rs. 11,800; find how much sweets of each kind were bought ?

Exercise 6 (G) | Q 8 | Page 94

Mr. and Mrs. Abuja weight x kg and y kg respectively. They both take a dieting course, at the end of which Mr. Ahuja loses 5 kg and weights as much as his wife weighed before the course. Mrs. Ahuja loses 4 kg and weighs `7/8`th of what her husband weighed before the course. Form two equations in x and y, find their weights before taking the dieting course.

Exercise 6 (G) | Q 9 | Page 94

A part of monthly expenses of a family is constants and the remaining vary with the number of members in the family. For a family of 4 person, the total monthly expenses are Rs. 10,400 whereas for a family of 7 persons, the total monthly expenses are Rs. 15,800. Find the constant expenses per month and the monthly expenses of each member of a family.

Exercise 6 (G) | Q 10 | Page 94

The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs. 315 and for a journey of 15 km, the charge paid is Rs. 465. What are the fixed charges and the charge per kilometer ? How much does a person have to pay for travelling a distance of 32 km ?

Exercise 6 (G) | Q 11 | Page 94

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Geeta paid Rs. 27 for a book kept for seven days, while Mohit paid Rs. 21 for the book he kept for five days. Find the fixed charges and the charge for each extra day.

Exercise 6 (G) | Q 12 | Page 94

The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. However, if the length of this rectangle increases by 3 units and the breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.

Exercise 6 (G) | Q 13 | Page 94

It takes 12 hours to fill a swimming pool using two pipes. If the pipe of larger diameter is used for 4 hours and the pipe of smaller diameter is used for 9 hours, only half of the pool is filled. How long would each pipe take to fill the swimming pool ?

Solutions for 6: Simultaneous (Linear) Equations (Including Problems)

Exercise 6 (A)Exercise 6 (B)Exercise 6 (C)Exercise 6 (D)Exercise 6 (E)Exercise 6 (F)Exercise 6 (G)
Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 6 - Simultaneous (Linear) Equations (Including Problems) - Shaalaa.com

Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 6 - Simultaneous (Linear) Equations (Including Problems)

Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE 6 (Simultaneous (Linear) Equations (Including Problems)) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 6 Simultaneous (Linear) Equations (Including Problems) are Methods of Solving Simultaneous Linear Equations by Elimination Method, Method of Elimination by Equating Coefficients, Equations Reducible to Linear Equations, Methods of Solving Simultaneous Linear Equations by Elimination Method, Methods of Solving Simultaneous Linear Equations by Cross Multiplication Method, Simultaneous method, Introduction to linear equations in two variables, Simple Linear Equations in One Variable.

Using Selina Concise Mathematics [English] Class 9 ICSE solutions Simultaneous (Linear) Equations (Including Problems) exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 9 ICSE students prefer Selina Textbook Solutions to score more in exams.

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