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10% of X + 20% of Y = 24 3x - Y = 20 - Mathematics

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Question

10% of x + 20% of y = 24
3x - y = 20

Sum

Solution

10% of x + 20% of y = 24
⇒ 0.1x + 0.2y = 24                  .....(1) [ On Simplyfying ]
3x - y = 20                               .....(2)

Multiply equation (2) by 0.2, We get :
 0.6x - 0.2y = 4                        ......(3)

Adding equation (3) and (1)
   0.6x - 0.2y = 4
+ 01x + 0.2y = 24 
              0.7x = 28
                  x = 40
Substituting x = 40 in equation (1), We get
0.1(40) + 0.2y = 24
⇒ 0.2y = 20
⇒ y = 100
∴ Solution is x = 40 and y = 100.

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Methods of Solving Simultaneous Linear Equations by Elimination Method - Method of Elimination by Equating Coefficients
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Chapter 6: Simultaneous (Linear) Equations (Including Problems) - Exercise 6 (B) [Page 81]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 6 Simultaneous (Linear) Equations (Including Problems)
Exercise 6 (B) | Q 15 | Page 81
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