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Question
The sum of two numbers is 8 and the difference of their squares is 32. Find the numbers.
Sum
Solution
Let two no's be x & y
x + y = 8 ...(i)
x2 - y2 = 32
(x + y) (x - y) = 32
8 (x - y) = 32
x - y = 4 ...(ii)
Adding equation (i) & (ii)
x + y = 8
x - y = 4
2x = 12
x = `12/2`
x = 6
From equation (i)
6 + y = 8
y = 8 - 6
y = 2
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