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Question
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`1/5( x - 2 ) = 1/4( 1 - y )`
26x + 3y + 4 = 0
Solution
`1/5( x - 2 ) = 1/4( 1 - y )`
⇒ 4( x - 2 ) = 5( 1 - y )
⇒ 4x - 8 = 5 - 5y
⇒ 4x + 5y = 13 .....(1)
26x + 3y = - 4 .....(2)
Multiplying equation no. (1) by 3 and(2) by 5.
12x + 15y = 39 .....(3)
130x + 15y = - 20 .....(4)
Subtracting equation (4) from (3)
12x + 15y = 39
- 130x + 15y = - 20
- - +
- 118 x = 59
x = `-59/118`
x = `-1/2`
From (1)
`4(-1/2)` + 5y = 13
5y = 13 + 2
y = 3
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