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Question
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`[5y]/2 - x/3 = 8`
`y/2 + [5x]/3 = 12`
Solution
The given pair of linear equations are
`[5y]/2 - x/3 = 8`
⇒ `- x/3 + [5y]/2 = 8` .....(1) [ On Similifying ]
`y/2 + [5x]/3 = 12`
⇒ `[5x]/3 + y/2 = 12` .....(2) [ On Similifying ]
Multiply equation (1) by 5, we get
` -[5x]/3 + [25y]/2 = 40` ......(3)
Adding equation (3) and (2)
` -[5x]/3 + [25y]/2 = 40`
+ `[5x]/3 + y/2 = 12`
`[26y]/2 = 52`
⇒ 13y = 52
⇒ y = 4
Substituting y = 4 in equation (1), We get
`- x/3 + [5(4)]/2 = 8`
⇒ `-x/3 = 8 - 10`
⇒ x = 6
∴ Solution is x = 6 and y = 4.
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