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Question
In an examination, the ratio of passes to failures was 4 : 1. Had 30 less appeared and 20 less passed, the ratio of passes to failures would have been 5 : 1. Find the number of students who appeared for the examination.
Sum
Solution
Let the no. of pass candidates be x
and the no. of fail candidates be y.
According to the question,
`x/y = 4/1`
x - 4y = 0 ...(1)
and
`[ x - 20 ]/[ y - 10 ] = 5/1`
x - 5y = -30 ...(2)
Subtracting equation (2) from (1),
x - 4y = 0
- x - 5y = - 30
- + +
y = 30
From (1)
x - 4(30) = 0
x = 120
Total students appeared = x + y = 120 + 30 = 150.
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