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Question
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 1.2
Solution
log 2 = 0.3010 and log 3 = 0.4771
log 1.2
= log`12/10`
= log 12 - log 10 ...[ loga`m/n` = logam - logan ]
= log 2 x 2 x 3 - 1 ...[ ∵ log 10 = 1 ]
= log 2 x 2 + log 3 - 1 ...[ logamn = logam + logan ]
= log 22 + log 3 - 1
= 2log2 + log3 - 1 ...[ nlogam = logamn ]
= 2( 0.3010 ) + 0.4771 - 1 ...[ ∵ log 2 = 0.3010 and log3 = 0.4771 ]
= 1.0791 - 1
= 0.0791
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