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Question
Express the following as a single logarithm:
`2 "log" 3 - (1)/(2) "log" 16 + "log" 12`
Solution
`2 "log" 3 - (1)/(2) "log" 16 + "log" 12`
= `2 "log" 3 - (1)/(2) "log" 2^4 + "log" (2^2 xx 3)`
= `2 "log" 3 - (1)/(2) xx 4 "log" 2 + "log" 2^2 + "log" 3`
= 2 log 3 - 2 log 2 + 2 log 2 + log 3
= 3 log 3
= log 33
= log 27.
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