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Question
Prove that : (log a)2 - (log b)2 = log `(( a )/( b ))` . Log (ab)
Solution
L.H.S = ( log a )2 - ( log b )2
⇒ L.H.S = ( log a + log b ) ( log a - log b )
⇒ L.H.S = log ( ab ) log `(( a )/( b ))`
⇒ L.H.S = log `(( a )/( b ))` x log ( ab)
⇒ L.H.S = R.H.S
Hence proved.
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