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Question
If log10 8 = 0.90; find the value of : log 0.125
Solution
Given that log108 = 0.90
⇒ log102 x 2 x 2 = 0.90
⇒ log1023 = 0.90
⇒ 3log102 = 0.90
⇒ log102 = `0.90/3`
⇒ log102 = 0.30 ...(1)
log 0.125
= log10`125/1000`
= log10`1/8`
= `log_10 (1/(2 xx 2 xx 2))`
= `log_10(1/2^3)`
= log102-3
= - 3 x ( 0.30 ) [ from(1) ]
= - 0.9
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