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Solve for X : Log (X + 5) + Log (X - 5) = 4 Log 2 + 2 Log 3 - Mathematics

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Question

Solve for x : log (x + 5) + log (x - 5) = 4 log 2 + 2 log 3

Sum

Solution

log ( x + 5 ) + log ( x - 5 ) = 4log2 + 2log3

⇒ log ( x + 5 ) ( x - 5 ) = 4log 2 + 2log3  ...[ logam + loga n + loga mn]

⇒ log ( x2 - 25 ) = log2 + log32            ... [ n loga m = loga mn ]

⇒ log ( x2 - 25 ) = log 16 + log9

⇒ log ( x2 - 25 )= log 16 x 9           ...[ loga m + loga n + loga mn]  

⇒ log ( x2  - 25 ) = log 144

⇒ x2 - 25 = 144

⇒ x = 144  + 25 

⇒ x = 169

⇒ x = `+-sqrt169`

⇒ x =`+-sqrt(13^2)`

⇒ x =`+-` 13

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Laws of Logarithm
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Chapter 8: Logarithms - Exercise 8 (B) [Page 106]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 8 Logarithms
Exercise 8 (B) | Q 7.4 | Page 106
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