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Given: Log3 M = X and Log3 N = Y. Express 32x - 3 in Terms of M. - Mathematics

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Question

Given: log3 m = x and log3 n = y.
Express 32x - 3 in terms of m.

Sum

Solution

Given that log3m = x and log3n = y
⇒ 3x = m and 3y = n 

Consider the given expression :
32x - 3
= 32x . 3-3
=` 3^(2x) . 1/3^3`

= `3^(2x)/3^3`

= `(3^x)^2/3^3`

= `m^2/27`
Therefore, 32x - 3 = `m^2/27`

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Expansion of Expressions with the Help of Laws of Logarithm
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Chapter 8: Logarithms - Exercise 8 (C) [Page 108]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 8 Logarithms
Exercise 8 (C) | Q 5.1 | Page 108
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