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प्रश्न
Given: log3 m = x and log3 n = y.
Express 32x - 3 in terms of m.
उत्तर
Given that log3m = x and log3n = y
⇒ 3x = m and 3y = n
Consider the given expression :
32x - 3
= 32x . 3-3
=` 3^(2x) . 1/3^3`
= `3^(2x)/3^3`
= `(3^x)^2/3^3`
= `m^2/27`
Therefore, 32x - 3 = `m^2/27`
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