Solve for X, Log_X^(15√5) = 2 - Log_X^(3√5) - Mathematics

Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.

Sum

log_x15√5 = 2 - log_x3√5

⇒ log_x15√5 + log_x3√5 = 2

⇒ log_x( 15√5 x 3√5 ) = 2

⇒ log_x225 = 2

⇒ log_x15² = 2

⇒ 2log_x15 = 2

⇒ log_x15 = 1
⇒ x = 15.

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Chapter 8: Logarithms - Exercise 8 (D) [Page 111]

Chapter 8 Logarithms
Exercise 8 (D) | Q 18 | Page 111

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