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Question
Find the logarithm of : `1/16` to the base 4
Sum
Solution
Let log4`1/16` = x
∴ 4x = `1/16`
⇒ 4x = `1/[ 4 xx 4 ]`
⇒ 4x = ( 4 x 4 )-1
⇒ 4x = ( 42 )-1
⇒ 4x = 4-2
⇒ x = - 2 ....[ If am = an ; then m = n ]
∴ log4`1/16` = - 2
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Interchanging Logarithmic and Exponential Forms
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