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Question
`inte^x(1/x - 1/x^2) dx` = ______ + c.
Fill in the Blanks
Solution
`inte^x(1/x - 1/x^2) dx = bbunderline(e^x/x)` + c
Explanation:
`d/dx(e^x/x) = (e^x.x - e^x.1)/x^2`
= `e^x((x - 1)/x^2)`
= `e^x(1/x - 1/x^2)`
Thus,
`inte^x(1/x - 1/x^2) dx = (e^x/x)` + c
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