HSC Commerce (English Medium)
HSC Commerce: Marketing and Salesmanship
HSC Commerce (Marathi Medium)
Academic Year: 2024-2025
Date & Time: 22nd February 2025, 11:00 am
Duration: 3h
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General Instructions:
- All questions are compulsory.
- There are six questions divided into two sections.
- Write answers of Section - I and Section - II in the same answer book.
- Use of logarithmic tables is allowed. Use of calculator is not allowed.
- For L.P.P. and Time Series graph paper is not necessary. Only rough shetch of graph is expected.
- Start answer to each question on a new page.
- For each objective type of question (ie. Q.1 and Q.4) only the first attempt will be considered for evaluation.
If p : He is intelligent
q : He is strong
Then, symbolic form of statement "It is wrong that, he is intelligent or strong" is:
− p ∨ − q
− (p ∧ q)
− (p ∨ q)
p ∨ − q
Chapter:
`int(x + 1/x)^3 dx` = ______.
`1/4(x + 1/x)^4 + c`
`x^4/4 + (3x^2)/2 + 3log x - 1/(2x^2) + c`
`x^4/4 + (3x^2)/2 + 3log x + 1/x^2 + c`
`(x - x^(-1))^3 + c`
Chapter: [0.015] Integration
`int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x)) dx` = ______.
`7/2`
`5/2`
7
2
Chapter: [0.016] Definite Integration [0.07] Definite Integrals
The area of the region bounded by the line y = 4 and the curve y = x2 is ______.
`32/3` square units
0 square unit
1 square unit
32 square units
`64/3` square units
`16/3` square units
64 square units
Chapter:
The order and degree of the differential equation `((d^2y)/(dx^2))^2 + ((dy)/(dx))^2 = a^x` are ______ respectively.
1, 1
1, 2
2, 2
2, 1
Chapter:
The integrating factor of the differential equation `(dy)/(dx) + y/x = x^3 −3` is ______.
log x
ex
`1/x`
x
Chapter:
If A is a matrix and K is a constant, then (KA)T = KAT
True
False
Chapter:
The differential equation obtained by eliminating arbitrary constants from bx + ay = ab is `(d^2y)/dx^2` = 0.
True
False
Chapter:
The average revenue RA is 50 and elasticity of demand η is 5, the marginal revenue RM is ______.
Chapter:
If f'(x) = x2 + 5 and f(0) = −1 then f(x) = ______.
Chapter:
Write the converse, inverse, and contrapositive of the statement "If a triangle is equilateral, then it is equiangular."
Chapter:
Find x, y, z, if `{5[(0, 1),(1, 0),(1, 1)] - [(2, 1),(3, - 2),(1, 3)]} [(2),(1)] = [(x - 1),(y + 1),(2z)]`
Chapter: [0.012] Matrices
Evaluate the following.
`int 1/(x(x^6 + 1))` dx
Chapter: [0.015] Integration
Solve the following equation by the method of inversion.
2x – y + z = 1,
x + 2y + 3z = 8,
3x + y – 4z = 1
Chapter: [0.012] Matrices
Find MPC, MPS, APC and APS, if the expenditure Ec of a person with income I is given as Ec = (0.0003) I2 + (0.075) I ; When I = 1000.
Chapter: [0.013999999999999999] Applications of Derivatives
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Evaluate:
`int_1^2 1/(x^2 + 6x + 5) dx`
Chapter: [0.016] Definite Integration
Find `dy/dx`if, y = `(x)^x + (a^x)`.
Chapter: [0.013000000000000001] Differentiation
Find the area of the region bounded by the parabola y2 = 25x and the line x = 5.
Chapter: [0.017] Applications of Definite Integration
Obtain the differential equation by eliminating arbitrary constants from the following equation:
y = Ae3x + Be–3x
Chapter: [0.018000000000000002] Differential Equation and Applications
Using the truth table, verify.
p ∨ (q ∧ r) ≡ (p ∨ q) ∧ (p ∨ r)
Chapter: [0.01] Mathematical Logic [0.011000000000000001] Mathematical Logic
If x = `(4t)/(1 + t^2), y = 3((1 - t^2)/(1 + t^2))` then show that `dy/dx = (-9x)/(4y)`.
Chapter: [0.013000000000000001] Differentiation
Divide the number 84 into two parts such that the product of one part and square of the other is maximum.
Solution:
Let one part be x then the other part will be 84 − x.
∴ f(x) = `square`
∴ f'(x) = 168x − 3x2
For extreme values f'(x) = 0
168x − 3x2 = 0
∴ 3x(56 − x) = 0
∴ x = `square or square`
f'(x) = 168 − 6x
If x = 0, f'(0) = 168 − 6(0) = 168 > 0
∴ function attains maximum at x = 0
If x = 56, f'(56) = `square` < 0
∴ function attains maximum at x = 56
∴ Two parts of 84 are `square and square`
Chapter:
Solve the following differential equation (x2 – yx2) dy + (y2 + xy2) dx = 0.
Separating the variables, the given equation can be written as:
`square dy + square dx = 0`
∴`(y^(-2) - 1/y)dy + (x^(-2) + 1/x)dx = 0`
`square dy - 1/y dy + x^(-2) dx + square dx = 0`
Integrating, we get
`inty^(-2) dy - int1/y dy + int x^(-2)dx + int 1/x dx = 0`
∴ `y^(-1)/(-1) - square + x^(-1)/(-1) + square = c`
`-1/y - 1/x + log x - log y = c`
`log x - log y = square + c`
is the required solution.
Chapter:
An agent who gives a guarantee to his principal that the party will pay the sale price of goods is called ______.
Auctioneer
Del credere agent
Factor
Broker
Chapter: [0.021] Commission, Brokerage and Discount
In an ordinary annuity, payments or receipts occur at ______.
Beginning of each period
End of each period
Mid of each period
Quarterly basis
Chapter: [0.022000000000000002] Insurance and Annuity
Moving averages are useful in identifying ______.
Seasonal component
Irregular component
Trend component
Cyclical component
Chapter: [0.024] Time Series
If P01(L) = 90 and P01(P) = 40, then P01(D – B) is ______.
65
50
25
130
Chapter:
The objective of an assignment problem is to assign ______.
Number of jobs to equal number of persons at maximum cost.
Number of jobs to equal number of persons at minimum cost.
Only the maximize cost.
Only to minimize cost.
Chapter: [0.027000000000000003] Assignment Problem and Sequencing [0.15] Management Mathematics
The expected value of the sum of two numbers obtained when two fair dice are rolled is ______.
5
6
7
8
Chapter: [0.027999999999999997] Probability Distributions [0.14] Random Variable and Probability Distribution
Using the truth table verify that p ∨ (q ∧ r) ≡ (p ∨ q) ∧ (p ∨ r).
Chapter: [0.027999999999999997] Probability Distributions [0.14] Random Variable and Probability Distribution
Cyclic variation can occur several times in a year.
True
False
Chapter:
Cost of living index number is used in calculating purchasing power of money.
True
False
Chapter:
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The amount paid to the holder of the bill after deducting banker's discount is known as ______.
Chapter:
The simplest method of measuring trend of time series is ______.
Chapter: [0.024] Time Series
Quantity Index Number by Weighted Aggregate Method is given by ______.
Chapter: [0.025] Index Numbers
Compute the appropriate regression equation for the following data:
X | 1 | 2 | 3 | 4 | 5 |
Y | 5 | 7 | 9 | 11 | 13 |
X is the independent variable and Y is the dependent variable.
Chapter:
The company makes concrete bricks made up of cement and sand. The weight of a concrete brick has to be at least 5 kg. Cement costs ₹ 20 per kg and sand costs of ₹ 6 per kg. Strength consideration dictates that a concrete brick should contain minimum 4 kg of cement and not more than 2 kg of sand. Form the L.P.P. for the cost to be minimum.
Chapter: [0.026000000000000002] Linear Programming
Find the mean of the number of heads in three tosses of a fair coin.
Chapter: [0.027999999999999997] Probability Distributions
Obtain the trend value for the following data using 4-yearly centered moving averages:
Years | 1976 | 1977 | 1978 | 1979 | 1980 | 1981 | 1982 | 1983 | 1984 | 1985 |
Index | 0 | 2 | 3 | 3 | 2 | 4 | 5 | 6 | 7 | 10 |
Chapter:
Find the sequence that minimizes the total elapsed time to complete the following jobs in the order AB. Find the total elapsed time and idle times for both the machines.
Job | I | II | IIII | IV | V | VI | VII |
Machine A | 7 | 16 | 19 | 10 | 14 | 15 | 5 |
Machine B | 12 | 14 | 14 | 10 | 16 | 5 | 7 |
Chapter: [0.027000000000000003] Assignment Problem and Sequencing
Five cards are drawn successively with replacement from a well-shuffled deck of 52 cards. What is the probability that
- all the five cards are spades?
- only 3 cards are spades?
- none is a spade?
Chapter:
A house valued at ₹ 8,00,000 is insured at 75% of its value. If the rate of premium is 0.80%, find the premium paid by the owner of the house. If agent’s commission is 9% of the premium, find agent’s commission.
Chapter: [0.022000000000000002] Insurance and Annuity
Solve the following L.P.P. by graphical method:
Maximize: Z = 4x + 6y
Subject to 3x + 2y ≤ 12, x + y ≥ 4, x, y ≥ 0.
Chapter: [0.026000000000000002] Linear Programming
Defects on plywood sheet occur at random with the average of one defect per 50 sq.ft. Find the probability that such a sheet has:
- no defect
- at least one defect
Use e−1 = 0.3678
Chapter: [0.027999999999999997] Probability Distributions [0.14] Random Variable and Probability Distribution
The equations of two regression lines are 10x − 4y = 80 and 10y − 9x = − 40 Find:
- `bar x and bar y`
- bYX and bXY
- If var (Y) = 36, obtain var (X)
- r
Chapter: [0.023] Linear Regression
Find x if the cost of living index is 150.
Group | Food | Clothing | Fuel & Lighting | House Rent | Miscellaneous |
I | 180 | 120 | 300 | 100 | 160 |
W | 4 | 5 | 6 | x | 3 |
Chapter: [0.025] Index Numbers
A bill of ₹ 18,000 was discounted for ₹ 17,568 at a bank on 25th October 2017. If the rate of interest was 12% p.a., what is the legal due date?
Solution:
Given SD = ₹18,000, CV = ₹17,568
r = 12% p.a.
Now, BD = `square`
= 18,000 − 17,568
= ₹ 432
Also, BD = `square`
∴ `432 = (18,000 xx n xx 12)/100`
`n = (432 xx 100)/(18,000 xx 12)`
`n = 1/5` years = `square` days
The period for which the discount is deducted is 73 days, which is counted from the date of discounting, i.e., 25th October 2017:
October | November | December | January | Total |
6 | 30 | 31 | 6 | 73 |
Hence, legal due date is `square`
Chapter:
Solve the following assignment problem to maximization:
I | II | III | IV | V | |
1 | 18 | 24 | 19 | 20 | 23 |
2 | 19 | 21 | 20 | 18 | 22 |
3 | 22 | 23 | 20 | 21 | 23 |
4 | 20 | 18 | 21 | 19 | 19 |
5 | 18 | 22 | 23 | 22 | 21 |
Step - I
Subtract the Smallest element of each row from every element of that row
I | II | III | IV | V | |
1 | 0 | 6 | 1 | 2 | 4 |
2 | 1 | 3 | 2 | 0 | 3 |
3 | 2 | 3 | 0 | 1 | 3 |
4 | 2 | 0 | 3 | 1 | 1 |
5 | 0 | 4 | 5 | 4 | 3 |
Step - II
Subtract the smallest element of each column from every element of that column:
I | II | III | IV | V | |
1 | 0 | 6 | 1 | 2 | 4 |
2 | 1 | 3 | 2 | 0 | 3 |
3 | 2 | 3 | 0 | 1 | 2 |
4 | 2 | 0 | 3 | 1 | 0 |
5 | 0 | 4 | 5 | 4 | 2 |
Step - III
Draw minimum number of lines covering all zeros.
I | II | III | IV | V | |
1 | 0 | 6 | 1 | 2 | 4 |
2 | 1 | 3 | 2 | 0 | 3 |
3 | 2 | 3 | 0 | 1 | 2 |
4 | 2 | 0 | 3 | 1 | 0 |
5 | 0 | 4 | 5 | 4 | 2 |
Step - 1V
The smallest uncovered element is 1, which is to be subtracted from all uncovered elements and add it to all elements which lie at the intersection of two lines:
I | II | III | IV | V | |
1 | 0 | 5 | 0 | 3 | |
2 | 2 | 3 | 2 | 0 | 3 |
3 | 3 | 3 | 0 | 2 | |
4 | 3 | 0 | 3 | 1 | 0 |
5 | 0 | 3 | 4 | 3 |
Step - V
Draw minimum number of lines that are required to cover all zeros:
I | II | III | IV | V | |
1 | 0 | 5 | 0 | 1 | 3 |
2 | 2 | 3 | 2 | 0 | 3 |
3 | 3 | 3 | 0 | 1 | 2 |
4 | 3 | 0 | 3 | 1 | 0 |
5 | 0 | 3 | 4 | 3 | 1 |
Here minimum number of Lines = order of matrix.
Step - VI
Find smallest uncovered element (1). Subtract this number from all uncovered elements and add it to all elements which lie at the intersection of two lines:
I | II | III | IV | V | |
1 | 0 | 4 | 0 | 0 | 2 |
2 | 3 | 3 | 3 | 0 | 3 |
3 | 3 | 0 | 0 | ||
4 | 3 | 0 | 3 | 1 | 0 |
5 | 0 | 2 | 4 | 3 | 0 |
Now minimium number of lines = order of matrix.
The optimal assignment can be made.
Optimal solution is
1 → I
2 → IV
3 → `square`
4 → `square`
5 → V
Minimum value = `square`
Chapter:
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