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Question
Using the truth table verify that p ∨ (q ∧ r) ≡ (p ∨ q) ∧ (p ∨ r).
Solution
p | q | r | q ∧ r | p ∨ q | p ∨ r | p ∨ (q ∧ r) | (p ∨ q) ∧ (p ∨ r) |
T | T | T | T | T | T | T | T |
T | T | F | F | T | T | T | T |
T | F | T | F | T | T | T | T |
T | F | F | F | T | T | T | T |
F | T | T | T | T | T | T | T |
F | T | F | F | F | F | F | F |
F | F | T | F | T | F | F | F |
F | F | F | F | F | F | F | F |
From the above table all entries in the last two columns are identical.
p v (q Λ r) = (p v q) Λ (p v r)
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