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Question
Expand.
(4 − p)3
Sum
Solution
(4 − p)3
(a − b)3 = a3 − 3a2b + 3ab2 − b3
= `(4)^3 - 3 xx (4)^2 (p) + 3 xx 4 xx(p)^2 - (p)^3`
= `64 - 3 xx 16 xx p + 12p^2 - p^3`
= `64 - 48p + 12p^2 - p^3`
(4 − p)3 = `64 - 48p + 12p^2 - p^3`
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