English
Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

Expand: (3a – 4b)3 - Mathematics

Advertisements
Advertisements

Question

Expand: (3a – 4b)

Sum

Solution

(a – b)3 = a3 – b3 – 3ab(a – b)

(3a – 4b)3 = (3a)3 – (4b)3 – 3(3a)(4b)(3a – 4b)

= 27a3 – 64b3 – 36ab(3a – 4b)

= 27a3 – 64b3 – 108a2b + 144ab2

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Algebra - Exercise 3.4 [Page 101]

APPEARS IN

Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 3 Algebra
Exercise 3.4 | Q 4. (i) | Page 101
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×