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Explain the following: Pb4+ acts as an oxidising agent but Sn2+ acts as a reducing agent. - Chemistry

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Question

Explain the following:

Pb4+ acts as an oxidising agent but Sn2+ acts as a reducing agent.

Short Note

Solution

Inert pair effect is less prominent in Sn than in Pb. Therefore, +2 oxidation of Sn is less stable than its +4 oxidation state. In other words, Sn2+ can easily lose two electrons to form Sn4+ and hence Sn2+ acts as a reducing agent.

\[\ce{Sn^{2+} -> Sn^{4+} + 2e}\]

In contrast, the inert pair effect is more prominent in Pb than in Sn. Therefore, +2 oxidation state of Pb is more stable than its +4 oxidation state. In other words, Pb4+ can easily lose two electrons to form Pb2+ and hence Pb4+ acts as an oxidising agent.

\[\ce{Pb^{4+} + 2e– -> -Pb^{2+}}\]

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Group 13 Elements - The Boron Family
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Chapter 11: The p-block Elements - Multiple Choice Questions (Type - I) [Page 138]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 33.(v) | Page 138

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