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Question
Explain the following reaction with the balanced equation.
Reaction of zinc with dil hydrochloric acid
Short Note
Solution
Zinc, on treatment with dilute hydrochloric acid, forms zinc chloride with release of hydrogen gas.
\[\ce{\underset{\text{Zinc}}{Zn_{(s)}} + \underset{\text{Hydrochloric acid}}{2HCl_{(aq)}} -> \underset{\text{Zinc chloride}}{ZnCl_{2(aq)}} + \underset{\text{Hydrogen}}{H2↑}}\]
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