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Explain the Octet Rule for the Formation of – Sodium Chloride from a Sodium Atom and a Chlorine Atom. - Chemistry

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Question

Explain the octet rule for the formation of –

Sodium chloride from a sodium atom and a chlorine atom.

Answer in Brief

Solution

Formation of sodium chloride NaCl, Na atom has atomic number 11 [2, 8, 1], There is 1 electron in the outermost M shell it is not possible to gain 7 electrons and to lose 1 electron is easier, by losing sodium atom because of \[\ce{Na+}\] ion.
While Cl atomic number 17 [2, 8, 7] has 7 electrons in outermost M shell for Cl atom it is easier to gain 1 electron, becomes \[\ce{Cl-}\] ion.
By losing 1 electron and by gaining 1 electron both sodium and chlorine attain octet configuration and become stable and there is the electrostatic force that pulls them and becomes sodium chloride.

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Chapter 4: Atomic Structure & Chemical Bonding - Additional Questions

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Viraf J. Dalal Simplified ICSE Chemistry [English] Class 9
Chapter 4 Atomic Structure & Chemical Bonding
Additional Questions | Q 16.1
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