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Question
factorise: 54a2b2 - 6
Sum
Solution
54a2b2 - 6
= 6(9a2b2 - 1) = 6[(3ab)2 - (1)2]
= 6 (3ab - 1)(3ab + 1)
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Factorisation of Trinomials
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factorise: 54a2b2 - 6
54a2b2 - 6
= 6(9a2b2 - 1) = 6[(3ab)2 - (1)2]
= 6 (3ab - 1)(3ab + 1)